What will be the output of the final print(x) statement, and why? developers

2024-09-23 20:16

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發文後	用戶	內容
25 分鐘內	tidah.yat	5
5 小時內	Teteu Costela teteu_costelinha	5 because you’re printing the variable “x” not the output of the tricky_func
5 小時內	Raymond Wong starry2011night	pass by value
18 小時內	Wil Laan willaanatwillaannl	The returned value is still on the stack somewhere, but x is unchangrd because the parameter is not a referenced. You should write x=tricky_func(x)
5 個月內	Muhammad Ali Abdullah abdullah.pro.dev	5 is ans