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2024-10-04 00:52
X^2 -11x +28 =0 (X-7)(x-4)=0 X= 7, 4
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Patrick Jerome Ngo
pjngo21
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Pranav
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X is not 4. Since we are squaring both sides, it was not initially a quadratic. So only one actual root. X as 4 gives sqrt(1) as -1 which is incorrect technically. It’s only right if we square both sides to get 1=1 as the root function returns only positive