Print the numbers from 1 to 100. But without using any loops (for, while, do-while). What’s your approach?

2024-11-04 20:17

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一小時內	Marek \| Editor & Programátor nytrdev	def num1_10(i): print(i) if i == 100: return num1_10(i+1) num1_10(1)
2 小時內	hub_bub	Type 1 in excel and drag that box to row 100 😛
6 小時內	Atharv Sawarkar athdoesnotcode	def a(target, now=1): if now > target: return now print(now) a(target, now+1) a(100)
21 小時內	Nick intrinsic_nerd	In c# with recursion where ‘i’ is the number to reach: void exec(int i){ if (i != 1) exec(i-1); Console.WriteLine(i); }
一天內	Daniel Pereira Volpato volpato.daniel	"evil" GOTO