Let’s do this MathThreads

2024-11-28 12:10

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發文後	用戶	內容
19 小時內	楊禮嗣 mathematic00yang	f(x)=0
21 小時內	蔡承希 1120jason	Let z=f’(x) -> z’=z^2 Obviously, Separable ODE: general solution -1/z = x + c -> z=f’(x)=-1/(x+c) -> f(x)=-ln\|x+c1\|+c2 with singular solutions z=0 -> f(x)=c
一天內	Owen Mok owen_mok	Divide both sides by f’(x)^2, integrate once, we have -1/f’ = x+C. Therefore f(x)=- ln\|x+C\|+K, where C and K are arbitrary constants.